Buying plane tickets for adults and children. But starting from 12 years, what category does a person belong to?

vs.

When your industry's conception of a word is different from general usage, be specific and open about it.
Buying plane tickets for adults and children. But starting from 12 years, what category does a person belong to?
vs.
When your industry's conception of a word is different from general usage, be specific and open about it.
Use:
@media(hover: hover) and (pointer: fine) {}
Spec not finalized, but so far so good.
Source: https://medium.com/@mezoistvan/finally-a-css-only-solution-to-hover-on-touchscreens-c498af39c31c
When should I close (i.e. delete) the branch after a successful pull request? Rule of thumb: always. (There are exceptions of course.)
What if I need to recover the deleted work? You'll just
git checkout -b <branch> <sha>
Each $q.reject() throws an error if not being chained properly. First check that all calls have a .catch(). Second, if possible, isolate your error cases to an independent describe block. Example below using bardjs, but the idea should be clear enough.
let stuffDataservice; const stuff = [{}]; beforeEach(function() { [...] stuffDataservice = { getStuff: function () { return $q.when(stuff); }, getSomethingElse: function () { return $q.when(somethingElse); } }); scope = $rootScope.$new(); controller = $controller('MyController', { $scope: scope, stuffDataservice: stuffDataservice }); }); describe('.getStuff()', function() { it('gets stuff', function() { scope.$apply(); expect(controller.stuff).toBe(stuff); }); describe('failure', function() { let failingController; beforeEach(function() { /* overrides previously defined $q.when */ stuffDataservice.getStuff = function() { return $q.reject(); }; /* new controller needed to make use of changes in dataservice */ failingController = $controller('MyController', { $scope: scope }); }); it('is handled', function() { scope.$apply(); expect(failingController.variableDescribingTheFailure).toBeDefined(); }); });
It's as simple as url.match(/\/\/(.[^/]+)/)[1]
. Requires the double slash before the domain part, but not a slash after it.